Lesson 20
Getting Started (Introduction to Differential Equations, continued)
We will begin this lesson by considering what a differential equation is and what a slope field represents.
The simplest definition of a differential equation is an equation that involves a derivative. In calculus, you will learn how to find the derivative of a function and what it means. A “derivative” is represented by a form similar to dy/dx or y’. A “differential equation” is an equation that contains derivatives.
The simplest definition of a derivative is that it is the rate of change (slope) of the function at a given x-value. For example, if the function is linear, the slope is a constant rate of change and so the derivative is constant. Given y=3x+1, we know that the slope is 3 and so y’=3.
If the function is not linear, the derivative is very useful! It helps us find the rate of change at any individual point on the function.
To draw a slope field, we can use dy/dx or y’ to find the slope of the original curve at a single x-value. We then draw a short segment about the x-value that has the estimated slope (dy/dx). If we do this enough times, we will be able to visualize the original curve!

Before beginning Part 1...
1. Download the Virtual ClassPad file (vcp file)
- Click Lesson_20.vcp
- Choose the Save or Save As… option
- Open the Save in dropdown box (near top)
- Brows to your My Documents folder and select it
- Select the CASIO folder and then the ClassPad Manager folder
- Click Save
- Click Open Folder
- Double click on Lesson_20.vcp to open it
2. Alternative way to open a Virtual ClassPad File
- Right click on your ClassPad (a "context menu" will appear)
- Select File and then Open...
- Browse to your Lesson_20.vcp file (It should be in My Documents/CASIO/ClassPad Manager folder)
- Select Lesson_20.vcp
- Click Open
Part I
In this part, you will learn how to graph a 1st order differential equation and try to understand what the graph represents.
1. Graphing a Slope Field for a 1st Order Differential Equation

2. Inputting an Initial Condition Point using the IC Page

Notice that the solution curves we draw are linear! Does this make sense? Hmmm…
y’=2 (a constant) which implies that the original equation is a linear equation with a slope of 2. The original must be of the form y=2x+b. But, we would need additional information to find the exact value of b.
We could find b for (2,-3) and (1, 3).
For (2,-3) y=2x+b becomes -3=2*2+b -> b=-3-4=-7
What will b equal for (1, 3)? Guess by looking at the above graph!
3. Graphing Solution Curves by Guessing an Equation

Part I
Practice Exercises
Before beginning the practice exercises, open a word document, type in the following information and then save it as Lesson20 in your CASIO folder within My Documents:
- Date: (enter today's date)
- To: (put your instructor's name here)
- From: (put your name here)
- Re: Lesson 20
- Please begin by opening the DiffEqGraph application.
- Click the Graph tab and select Edit/Clear All.
- Click the IC tab and select Edit/Clear All.
- Click the DiffEq tab and select Edit/Clear All.
- Following y', input 1/y and press EXE.
- Display the graph.
- With your equation and graph showing, get a screen capture. Paste it into your Lesson20 document (under a title of PART I).
- Click the IC tab and input x=1, y=2 and x=1, y=-2 for initial conditions.
- Display the graph with solution curves.
- With your equation and graph showing, get a screen capture. Add two blank spaces following the first screen capture and then paste this one.
- Click the Graphs tab. Following y, input (2x)^(1/2) and press EXE.
- Place focus on the line containing (2x)^(1/2) and change the line style to be thicker.
- Display the Graph.
- With your equation and graph showing, get a screen capture. Add two blank spaces following the last screen capture and then paste this one.
- Please clear the DiffEq page, IC page and the Graphs page. Each needs to be done separately.